Math

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Of course it is. But he didn't say a=1. If he had, that wouldn't be an analytical problem, merely a numerical one.

-thanos

 

How about, x > 0...maybe?

Why must I see this Math thread today?! Just when I was trying to avoid doing my math homework peacefully, so that I'd have to study for my Calculus quiz tomorrow on the bus to school, I see this #!^&*#!@*& thread, and now I have to study...

 

We'll help with your studying Faerus

Anyway - Nobleman, the answer would just be 0, wouldn't it?

 

It can't be 0, because a is greater than 0. 1 seems like the most likely answer.

[Edit] Scratch that, I actually thought about this now 0 is also a possible solution for x.

[Edit 2] Scratch what I just said. All this mechanics I've been doing has confused me 0 can't be an answer, because you can't have 0 to the power of 0, at least as far as I know.

[ September 19, 2002, 16:33: Message edited by: Wildfire ]

 

Guys:

IT CAN'T BE A NUMBER.
It has to be something that has 'a' in it. That's why it's called an analytical solution

Example: x^2 =a => x=(+-) sqrt(a)

No numbers.

-thanos

 

This may not make sense - but could it be -0.5

 

You're mean, Nobleman. I'll bring this to my friends at school and see what they can find out. And if any of you would care to help me with something I had on my math test today:

Find g(100) from g(t)=7-[11cos(2*pi*t/365)+5sin(2*pi*t/365)]

I just hope this is something we haven't learned yet, and that it doesn't count in the final results . I have trouble finding the meaning of the [] around parts of the function.

[ September 19, 2002, 18:34: Message edited by: Mollusken ]

 

And what's the exact difference between () and []?

[ September 19, 2002, 19:17: Message edited by: Mollusken ]

 

ooh, I love math thingies for fun.
I'd the say the answer would be a>0, for x=[0,unlimited[

0 is in because, something^0 = 1

positive, well, that should be obvious, gets bigger

no negatives due to the very first x would always make it negative.

did I mess up, or are you supposed to start playing with them exp and logaritme natural(sp?), ln for short, thingies?

[ September 19, 2002, 20:08: Message edited by: Lokken ]

 

Negative even numbers are in too because (-2)^-2 becomes 1/(-2)^2 = 1/4 which is bigger than zero.

However, negative odd numbers are out because you will end up with a negative fraction. and a < 0 is not allowed.

Don't ask me how to write that in bracket notation

 

I'd say ANY negative number is out. It's an exponent tower, right? So .... * 1/2 * 1/3 * 1/4... = 0.

AFAIK 0 and 1 are the only values for X that will yield a finite a greater than 0.

[EDIT] Can you actually have 0^0? Is that valid? I mean, 0 * anything = 0, but anything ^ 0 = 1... I guess this doesn't include 0, then? [/EDIT]

[ September 20, 2002, 00:29: Message edited by: Judas ]

 

Oh is that the definition for an exponent tower?

I was just trying to solve X^X^X^X^... >0

I wasn't thinking about X^(X+1)^(X+2)^(X+3)... >0
or any other sequence that the exponent changes its value.

 

All numbers to the power of 0 = 1 because x^0 = x/x = 1 (any number divided by itself equals one of course)

Now try zero..... It is nonsense to divide anything by nothing, including nothing, so no 0^0 does not equal 1. If anything it is infinite.

So now at least we know that x is positive and also greater than zero.

We'll get there guys.

 

The only possible solutions are that X = (0, 1). Any other number would lead a to change infinitly. Unless infinity is acceptable as an answer.

Ugh. Too early for Math. Need java.

 

Mollusken = if t = 100 then G = -12.19 to 4 s.i.f

in full it'd be -12.18563814, but that was just me checking on my calc

 

It has been a while since I've seen any complex math, but I'm still confused as to what the actual question is.

Solve what?

Do you mean you want possible values X can take on? As we've previously discussed, anything other than 0 or 1 yields either a=positive infinity, or a=0.

On the note of 0^0=?, I looked it up. Sometimes it's 1, sometimes it's 0. I'm not kidding. I think there are rules decide when to use what. It is generally accepted that (i.e. in most cases, the appropriate value is) 0^0 = 1. This isn't any kind of proof, really, but calc.exe yields 0^0=1, as well.

Back to the question... if you're not after a range / set of possible values, it doesn't make much sense to me. Did you mean you want an expression to give you the nth term of the sequence X, X^X, X^X^X, X^X^X^X... ?

[ September 21, 2002, 00:40: Message edited by: Judas ]